(x^2)-14x-5=0

Solution for (x^2)-14x-5=0 equation:

(x^2)-14x-5=0

a = 1; b = -14; c = -5;
Δ = b2-4ac
Δ = -142-4·1·(-5)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-6\sqrt{6}}{2*1}=\frac{14-6\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+6\sqrt{6}}{2*1}=\frac{14+6\sqrt{6}}{2}
$